$a_{n} = (- 1)^{n - 1} n^{3}; a_{9}$

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Solution

We have, $a_{n} = (- 1)^{n - 1} n^{3}$
For, $a_{9}, n = 9$
$∴ a_{9} = {(- 1)}^{9 - 1} {(9)}^{3} = {(9)}^{3} = 729$

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