Question

$a\times b\theta c$ implies that

• A. $a\square c\theta b$
• B. $b\times a\square c$
• C. $c\square b+a$
• D. $a\varphi b\square c$

Answer 1

The correct option is D $a\varphi b\square c$

$a\times b\theta c$ is equivalent to $a<b=c$ Hence between a and b we have $a<b$ or $a\ne bora>b$
Further b = c implies that b and c are interchageable
Hence (1),(2) and (3) are not possible.
[Observation that (2) states $b<a$ which means $a>b$ which is not possible Similary in (3) $b>a$ which means $a<b$ which contradicts the hypothesis] (4) Is the correct answer which states that $a\ne bandb>c$ Both statements are possible