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Question

α and β are the positive acute angles and satisfying equations 5sin2β=3sin2α and tanβ=3tanα simultaneously. Then the value of tanα+tanβ is

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Solution

Given tanβ=3tanα
Also given 5sin2β=3sin2α
5(2tanβ1+tan2β)=3(2tanα1+tan2α)
30tanα1+9tan2α=6tanα1+tan2α
24tanα24tan3α=0
tanα=1,0,1
Since,α,β are positive acute angles
tanα=1
tanβ=3
tanα+tanβ=4

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