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Byju's Answer
Standard XII
Physics
Dimensional Analysis
α =F/v2sin β ...
Question
α
=
F
v
2
sin
(
β
t
)
(here v = velocity, F = force, t = time)
Find the dimension of
α
and
β
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Solution
α
=
F
v
2
sin
(
β
t
)
dimensionless dimensionless
⇒
[
β
]
[
t
]
=
1
=
[
β
]
=
[
T
−
1
]
So
[
α
]
=
[
F
]
V
2
=
[
M
1
L
1
T
−
2
]
[
L
1
T
−
1
]
2
=
M
1
L
−
1
T
0
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