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Introduction to Curves

ax2+by2+cz2+2...

Question

$a x^{2} + b y^{2} + c z^{2} + 2 a y z + 2 b z x + 2 c x y$ ; may be resolved into linear factors if $a, b, c$ are such that

a = b = c

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a b + b c + c a = 1

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a + b + c = 0

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none of these

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Solution

The correct options are
A $a = b = c$
C $a + b + c = 0$

Suggest Corrections

Similar questions

a x^{2} + b y^{2} + c z^{2} + 2 a y z + 2 b z x + 2 c x y

a^{3} + b^{3} + c^{3}

a x^{2} + b y^{2} + c z^{2} + 2 a y z + 2 b z x + 2 c x y

a x^{2} + 2 c x y + b y^{2} + 2 b x + 2 a y + c

a + c \neq 0

\frac{1}{a} + \frac{1}{a - b} + \frac{1}{c} + \frac{1}{c - b} = 0

a, b, c

H . P

a, b, c

a (b - c) x^{2} + b (c - a) x y + c (a - b) y^{2}

a, b, c

H . P

a x^{2} + 2 x (h y + g) + b y^{2} + 2 f y + c = 0

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