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B
(¯b⋅¯c)(¯aׯd)−(¯b⋅¯a)(¯bׯd)
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C
(¯b⋅¯d)(¯aׯc)−(¯b⋅¯c)(¯aׯd)
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D
(¯b⋅¯a)(¯bׯa)−(¯c⋅¯d)(¯cׯd)
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Solution
The correct option is D(¯b⋅¯d)(¯aׯc)−(¯b⋅¯c)(¯aׯd) ¯b×(¯cׯd)=(¯b.¯d)¯c−(¯b.¯c)¯d So, ¯a×{¯b×(¯cׯd)}=¯a×[(¯b.¯d)¯c−(¯b.¯c)¯d] =(¯b.¯d)(¯aׯc)−(¯b.¯c)(¯aׯd)