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B
12
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C
13
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D
14
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Solution
The correct option is C 13 Expanding, we get 47C4+47C3+48C3+49C3+50C3+51C3+52C3 Applying nCr+nCr+1=n+1Cr+1, we get [47C4+47C3+48C3+49C3+50C3+51C3] =+48C4+48C3+49C3+50C3+51C3] : : 51C3+51C4 =52C4. Hence x=52 and y=4 Hence, xy=524 =13