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Question

∣ ∣ ∣¯a¯a¯a¯b¯a¯c¯b¯a¯b¯b¯b¯c¯c¯a¯c¯b¯c¯c∣ ∣ ∣ is equal to

A
[¯a¯b¯c]3
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B
[¯a¯b¯c]2
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C
[¯a¯b¯c]
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D
None of these
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Solution

The correct option is B [¯a¯b¯c]2
Let
¯a=α1^i+α2^j+α3^k,
¯b=(β1,β2,β3)
¯c=(γ1,γ2,γ3)

then, ∣ ∣ ∣¯a¯a¯a¯b¯a¯c¯b¯a¯b¯b¯b¯c¯c¯a¯c¯b¯c¯c∣ ∣ ∣

=∣ ∣ ∣α21+α22+α23α1β1+α2β2+α3β3α1γ1+α2γ2+α3γ3α1β1+α2β2+α3β3β21+β22+β23β1γ1+β2γ2+β3γ3α1γ1+α2γ2+α3γ3β1γ1+β2γ2+β3γ3γ21+γ22+γ23∣ ∣ ∣

=∣ ∣α1α2α3β1β2β3γ1γ2γ3∣ ∣∣ ∣ ∣α1β1γ1α2β2γ2α3β3γ3∣ ∣ ∣

=[¯a¯b¯c]2

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