CN2g-2OH-aq-Products are-

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Standard XII

Chemistry

Ion Electron Method

CN2g+2OH-aq→P...

Question

$(C N)_{2} (g) + 2 O H^{-} (a q) \to Products$ are:

C N^{-}

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C N O^{-}

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H_{2} O

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All are correct

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Solution

The correct option is D All are correct
${C N}_{2} (g) + 2 {O H}^{-} (aq) ⟶ {C N}^{-} (aq) + {C N O}^{-} (aq) + H_{2} O$

In this reaction, $(C N)_{2}$ undergoes oxidation, as well as reduction, such reactions, are called disproportional reactions.

Hence, option D is correct.

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Similar questions

Q. What sorts of informations can you draw from the following reaction ?

(C N)_{2} (g) + 2 O H^{-} (a q) \to C N^{-} (a q) + C N O^{-} (a q) + H_{2} O (l)

Balance the following reaction:

M n O_{4}^{-} + C N^{-} + H_{2} O \to M n O_{2} + C N O^{-} + O H^{-}

What sorts of informations can you draw from the following reaction ?
$(C N)_{2 (g)} + 2 O H_{(a q)}^{-} ⟶ C N_{(a q)}^{-} + C N O_{(a q)}^{-} + H_{2} O_{(l)}$

Q. Balance the following chemical equation in basic medium:

M n O_{4}^{-} (a q) + B r^{-} (a q) \to M n O_{2} (s) + B r O_{3}^{-} (a q)

Q. Ambidentate ligands out of

P y, e n, C N S, C N, C N O, C_{2} O_{4}^{2 -}, N O_{2},

are:

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(CN)2(g)+2OH−(aq)→Products are:

The correct option is D All are correctCN2(g)+2OH−(aq) ⟶CN−(aq) +CNO−(aq) +H2OIn this reaction, (CN)2 undergoes oxidation, as well as reduction, such reactions, are called disproportional reactions.Hence, option D is correct.

$(C N)_{2} (g) + 2 O H^{-} (a q) \to Products$ are:

The correct option is D All are correct
${C N}_{2} (g) + 2 {O H}^{-} (aq) ⟶ {C N}^{-} (aq) + {C N O}^{-} (aq) + H_{2} O$

In this reaction, $(C N)_{2}$ undergoes oxidation, as well as reduction, such reactions, are called disproportional reactions.

Hence, option D is correct.