Question

$\cos {58}^{\circ }\cos {32}^{\circ }-\cos {58}^{\circ }\sin {58}^{\circ }$

Answer 1

$\cos {58}^{\circ }\cos {32}^{\circ }-\cos {58}^{\circ }\sin {58}^{\circ }$
= $\cos {58}^{\circ }\cos (90-58{)}^{\circ }-\cos {58}^{\circ }\sin {58}^{\circ }$
= $\cos {58}^{\circ }\sin {58}^{\circ }-\cos {58}^{\circ }\sin {58}^{\circ }$
= $0$