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Question

cosx+42sin(xπ4)+6

A
[1, 11]
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B
[-1, 11]
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C
[2,10]
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D
[11, 1]
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Solution

The correct option is D [1, 11]
f(x)=cosx+42sin(xπ4)+6

=cosx+42[sinx.cos(π/4)sin(π/4).cosx]+6

=cosx+4(sinxcosx)+6 ...........[sin(π/4)=cos(π/4)=1/2]
=4sinx3cosx+6
Range of 4sinx3cosx ϵ [42+32,42+32]
ϵ[5,5]
So, range of f(x)ϵ[5+6,5+6]
ϵ[1,11]

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