CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

cosx+42sin(xπ4)+6

A
[1, 11]
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
[-1, 11]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
[2,10]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
[11, 1]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D [1, 11]
f(x)=cosx+42sin(xπ4)+6

=cosx+42[sinx.cos(π/4)sin(π/4).cosx]+6

=cosx+4(sinxcosx)+6 ...........[sin(π/4)=cos(π/4)=1/2]
=4sinx3cosx+6
Range of 4sinx3cosx ϵ [42+32,42+32]
ϵ[5,5]
So, range of f(x)ϵ[5+6,5+6]
ϵ[1,11]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Composite Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon