You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sucrose

Δ Uo of combu...

Question

$Δ U^{o}$ of combustion of methane is $- X k J m o l e^{- 1}$ . The value of $Δ H^{o}$ is:

Δ U^{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Δ U^{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Δ U^{0}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

= 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B < $Δ U^{0}$
$Δ U^{o}$ of combustion of methane is $- X k J m o l e^{- 1}$ . The value of $Δ H^{o}$ is $< Δ U^{0}$
For the combustion of methane, $Δ n$ is negative.
Hence, $Δ H^{o} = Δ U^{o} + Δ n R T < Δ U^{o}$

Suggest Corrections

Similar questions

Δ U^{0}

C H_{4_{(} g)}

m o l^{- 1}

Δ H^{0}

Δ U^{o}

- X

k J

{m o l}^{- 1}

Δ H^{o}

Δ H^{0}

X_{(g)} + Y_{(g)} ⇌ Z_{(g)}

Δ U^{0}

227^{o} C

R = 2 c a l {m o l}^{- 1} K^{- 1}

Δ H^{0}

X_{(g)} + Y_{(g)} ⇌ Z (g)

- 4.6

Δ U^{0}

227^{0}

(R = 2 c a l . m o l^{- 1} K^{- 1})

2 K_{(g)} + L_{(g)} \to 2 M_{(g)}; Δ U^{0}

Δ S^{0}

K^{- 1}

Δ G^{0}

Join BYJU'S Learning Program