Question

$F=\frac{9}{5}C+32$ ; make 'C' the subject of formula.

• A. $C=\frac{5}{9}(F-32)$
• B. $C=\frac{9}{5}(F-32)$
• C. $C=\frac{5}{9}(F+32)$
• D. none of the above

Answer 1

The correct option is A $C=\frac{5}{9}(F-32)$

Given, $F=\frac{9}{5}C+32$

$\Rightarrow F-32=\frac{9}{5}C$

$\Rightarrow C=\frac{5}{9}(F-32)$