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Question

f(x)=x33x2+2xx33x2+2x.Find the set of points a, where limxaf(x) does not exist. Number of such points is?

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Solution

f(x)=|x(x1)(x2)|x(x1)(x2)=|x|x|x1|x1|x2|x2
Consider the points x=0,1,2;
We redefine the function,
f(x)=⎪ ⎪ ⎪ ⎪⎪ ⎪ ⎪ ⎪1x<0(1)(1)(1)=110<x<1(1)(1)(1)=111<x<2(1)(1)(1)=11x>2(1)(1)(1)=1
limf(x) as x0,1,2 does not exist as both R.H.L. and L.H.L. will be differnet.
Hence 0, 1, 2. are points of discontinuity.

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