Question

$f\left(x\right)=\frac{3}{2}x+b$
In the function above, $b$ is a constant. If $f\left(6\right)=7$, what is the value of $f(-2)$?

• A. -5
• B. -2
• C. 1
• D. 7

Answer 1

The correct option is A -5

Given, $f\left(x\right)=\frac{3}{2}x+b$, $f\left(6\right)=7$

$\Rightarrow f\left(6\right)=\frac{3\times 6}{2}+b=7$
$\Rightarrow 9+b=7$
$\Rightarrow b=-2$
Hence, $f(-2)=\frac{3\times (-2)}{2}-2=-5$