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Sulphur

FeOH 3 and ...

Question

${F e (O H)}_{3}$ and ${C r (O H)}_{3}$ precipitates are separated by :

A q . {N H}_{3}

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H C l

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N a O H / H_{2} O_{2}

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H_{2} {S O}_{4}

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Solution

The correct option is C $N a O H / H_{2} O_{2}$
${F e (O H)}_{3}$ and ${C r (O H)}_{3}$ precipitates are separated by $N a O H / H_{2} O_{2}$ . Chromium hydroxide is soluble in $N a O H / H_{2} O_{2}$ , whereas ferric hydroxide is insoluble.

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Similar questions

F e (O H)_{3}

C r (O H)_{3}

H_{2} O_{2} / {O H}^{-}, {C r (O H)}_{3}

{F e (O H)}_{3}

{C r (O H)}_{3}

C + O_{2} \to C O_{2}

H_{2} + C l_{2} \to H C l

N_{2} + H_{2} \to N H_{3}

F e + O_{2} \to F e_{2} O_{3}

100 m L

0.5 N

N a O H

20 m l

1 N

H C l

10 m L

3 N

H_{2} {S O}_{4}

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