${F e C}_{2} O_{4}$ can decolourise acidified ${K M n O}_{4}$ due to the oxidation of ${F e}^{2 +}$ and $C_{2} O_{4}^{2 -}$ .

If the given statement is true enter 1 else 0.

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Solution

${F e C}_{2} O_{4}$ can decolourise acidified ${K M n O}_{4}$ due to the oxidation of ${F e}^{2 +}$ and $C_{2} O_{4}^{2 -}$ .
Potassium permanganate is a strong oxidizing agent. it oxidizes ferrous ions to ferric ions and oxalate ions to carbon dioxide.

In this process, $M n (V I I)$ is reduced to $M n (I I)$ which results in decolourization.

$5 C_{2} O_{4}^{2 -} + 2 M n O_{4}^{-} ⟶ 2 {M n}^{2 +} + 10 C O_{2}$

$M n O_{4}^{-} + 5 F e^{2 +} + 8 H^{+} \to 5 F e^{3 +} + M n^{2 +} + 4 H_{2} O$

Hence, the given statement is true.

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