The correct option is C 0
(0.22)3+(0.11)3+(0.32)3(0.66)3+(0.96)3−(0.33)3+(0.32)3+(0.45)3−(0.77)381(0.32)(0.45)(0.77)
=8(0.11)3+(0.11)3+(0.32)3216(0.11)3+27(0.32)3+27(0.11)3−(0.32)3+(0.45)3−(0.32+0.45)381(0.32)(0.45)(0.77)
=9(0.11)3+(0.32)3243(0.11)3+27(0.32)3−(0.32)3+(0.45)3−(0.32+0.45)381(0.32)(0.45)(0.77)
=9(0.11)3+(0.32)327{9(0.11)3+(0.32)3}−(0.32)3+(0.45)3−[(0.32)3+(0.45)3+3(0.32)(0.45)(0.32)+(0.45)81(0.32)(0.45)(0.77)
=127−127
=0