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Question

(0.22)3+(0.11)3+(0.32)3(0.66)3+(0.96)3+(0.33)3−(0.32)3+(0.45)3−(0.77)381(0.32)(0.45)(0.77) equals

A
1
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B
111
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C
0
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D
-1
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Solution

The correct option is C 0
(0.22)3+(0.11)3+(0.32)3(0.66)3+(0.96)3(0.33)3+(0.32)3+(0.45)3(0.77)381(0.32)(0.45)(0.77)
=8(0.11)3+(0.11)3+(0.32)3216(0.11)3+27(0.32)3+27(0.11)3(0.32)3+(0.45)3(0.32+0.45)381(0.32)(0.45)(0.77)
=9(0.11)3+(0.32)3243(0.11)3+27(0.32)3(0.32)3+(0.45)3(0.32+0.45)381(0.32)(0.45)(0.77)
=9(0.11)3+(0.32)327{9(0.11)3+(0.32)3}(0.32)3+(0.45)3[(0.32)3+(0.45)3+3(0.32)(0.45)(0.32)+(0.45)81(0.32)(0.45)(0.77)
=127127
=0

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