$\frac{1 - c o s 2 A}{s i n 2 A} = t a n 2 A$
If above statement is true then mention answer as 1, else mention 0 if false

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Solution

Given, $A = 30^{\circ}$
Now, $\frac{1 - c o s 2 A}{s i n 2 A} = t a n A$
L.H.S: $\frac{1 - c o s 2 A}{sin 2 A}$
= $\frac{1 - c o s 2 (30^{0})}{sin 2 (30^{0})}$
= $\frac{1 - c o s 60^{0}}{sin 60^{0}}$
= $\frac{1 - \frac{1}{2}}{\frac{\sqrt{3}}{2}}$
= $\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}$
= $\frac{1}{\sqrt{3}}$
R.H.S: $tan A = tan 30^{0} = \frac{1}{\sqrt{3}}$
Thus, $L . H . S = R . H . S$

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