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Question

11+3+13+5+15+7+...... upto n terms. is equal to

A
2n+1
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B
12n+1+1
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C
n2n+1+1
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D
n2n+11
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Solution

The correct option is C n2n+1+1
Tn=12n1+2n+1=2n1+2n+12

Sn=Tn

=12[(31)+(53)+(7+5)+....+(2n+1)2n1]

=12[2n+11]=n2n+1+1

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