2x-1-x2-x4-1-1-x-x2-1-1-x-x2-

The correct option is D 0 2x/1+x^2+x^4+(1/1+x+x^2 1/1 x+x^2) =2x/1+x^2+x^4+((1 x+x^2) (1+x+x^2)/(1+x+x^2)(1 x+x^2)) =2x1+x^2+x^4 2x(1+x^2)^ ...

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Division of a Polynomial by a Polynomial

2x/1+x2+x4+1/...

Question

$\frac{2 x}{1 + x^{2} + x^{4}} + \frac{1}{1 + x + x^{2}} - \frac{1}{1 - x + x^{2}} =$

2 x

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x

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1

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Solution

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Similar questions

\sqrt{2 x} + \sqrt{- x^{4} - 1}

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\frac{1}{1 + x} + \frac{2 x}{1 + x^{2}} + \frac{4 x^{3}}{1 + x^{4}} + \dots \infty =

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\frac{1}{1 + x} + \frac{2 x}{1 + x^{2}} + \frac{4 x^{3}}{1 + x^{4}} + . . . . \infty

{sin}^{- 1} (\frac{2 x}{1 + x^{2}})

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1,

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{sin}^{- 1} (\frac{2 x}{1 + x^{2}}) = {cos}^{- 1} (\frac{1 - x^{2}}{1 + x^{2}})

- 1 \leq x \leq 1

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