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Question

3cosθ+cos3θ3sinθsin3θ is equal to-

A
1+cot2θ
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B
cot4θ
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C
cot3θ
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D
2cotθ
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Solution

The correct option is B cot3θ
3cosθ+cos3θ3sinθsin3θ
we know that sin3x=3sinx4sin3x and cos3x=4cos3x3cosx
=3cosθ+4cos3θ3cosθ3sinθ3sinθ+4sin3θ
=4cos3θ4sin3θ=cot3θ

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