$\frac{4}{11} + \frac{7}{11}$ = ..........

\frac{11}{22}

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\frac{11}{11}

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\frac{3}{11}

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11

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Solution

The correct option is B $\frac{11}{11}$
$\frac{4}{11} + \frac{7}{11} = \frac{4 + 7}{11} = \frac{11}{11}$

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Similar questions

\frac{4}{11} + \frac{7}{11} =

{sin}^{- 1} \frac{4}{5} + 2 {tan}^{- 1} \frac{1}{3} = \frac{π}{2}

{tan}^{- 1} \frac{1}{7} + 2 {tan}^{- 1} \frac{1}{3} = \frac{π}{4}

{tan}^{- 1} \frac{1}{5} + {tan}^{- 1} \frac{1}{7} + {tan}^{- 1} \frac{1}{3} + {tan}^{- 1} \frac{1}{8} = \frac{π}{4}

\frac{4 \times 22 \times 6.67 \times 10^{- 11} \times 6.4 \times 10^{6} \times 11 \cdot 3 \times 10^{3}}{3 \times 7}

$t a n^{- 1} \frac{1}{5} + t a n^{- 1} \frac{1}{7} + t a n^{- 1} \frac{1}{3} + t a n^{- 1} \frac{1}{8} = \frac{π}{4}$

t a n^{- 1} \frac{1}{3} + t a n^{- 1} \frac{1}{7} + t a n^{- 1} \frac{1}{5} + t a n^{- 1} \frac{1}{8} = \frac{π}{4} .

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