5 - 7 - 4 - 7 - 3 - 7 is equal to

The correct option is D 6 / 7 #160; #160; 5 / 7 + #160; 4 / 7 #160; 3 / 7 = 5+4 3 / 7 = #160; #160; 6 / 7 #160; ...

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Byju's Answer

Standard XII

Mathematics

Algebra of Complex Numbers

5 / 7 + 4 / 7...

Question

$\frac{5}{7} + \frac{4}{7} - \frac{3}{7}$ is equal to

\frac{3}{7}

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\frac{5}{7}

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\frac{6}{7}

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\frac{12}{7}

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Solution

The correct option is D $\frac{6}{7}$
$\frac{5}{7} + \frac{4}{7} - \frac{3}{7} = \frac{5 + 4 - 3}{7} = \frac{6}{7}$

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Similar questions

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

\frac{4}{7} - \frac{5}{7^{2}} + \frac{4}{7^{3}} - \frac{5}{7^{4}} + \frac{4}{7^{5}} - \frac{5}{7^{6}} + . . . .

to infinity.

Q. Median of the following numbers:

4, 4, 5, 7, 6, 7, 7, 12, 3

Q. Question 23
Median of the following numbers
4, 4, 5, 7, 6, 7, 7, 12, 3 is:

A) 4
B) 5
C) 6
D) 7

Fill in the blanks.

(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

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57+47−37 is equal to

The correct option is D 6757+47−37=5+4−37=67

$\frac{5}{7} + \frac{4}{7} - \frac{3}{7}$ is equal to

The correct option is D $\frac{6}{7}$
$\frac{5}{7} + \frac{4}{7} - \frac{3}{7} = \frac{5 + 4 - 3}{7} = \frac{6}{7}$