7x3-3x2-x-1-x-1-ax2-bx-c-2-x-1 then a-

The correct option is A 7 LHS=7x^3+3x^2 x+1/x+1; #160; RHS=ax^2+bx+c (2/x+1) RHS=(ax^2+bx+c)[x+1] 2x+1 LHS = RHS Comparing the co efficie ...

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Sum of Product of Binomial Coefficients

7x3+3x2-x+1/x...

Question

$\frac{7 x^{3} + 3 x^{2} - x + 1}{x + 1} = (a x^{2} + b x + c) - \frac{2}{x + 1}$ then $a =$

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If $(x^{3} - 3 x^{2} - x + 3)$ is divided by (x-1) we get $a x^{2} - b x + c$ , then value of (a+b+c)

\frac{x^{4} + 1}{(x - 1) (x - 2)} = A x^{2} + B x + C - \frac{2}{x - 1} + \frac{17}{x - 2}

C =

y = \frac{a x^{2}}{(x - a) (x - b) (x - c)} + \frac{b x}{(x - b) (x - c)} + \frac{c}{x - c} + 1

\frac{y^{4}}{y}

= \frac{1}{a x^{2} + b x + c}

=

f (x) = x^{3} + a x^{2} + b x + c

x = - 1

x = 3

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