CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Local Maxima

a+1/a2+5a×a2-...

Question

$\frac{a + 1}{a^{2} + 5 a} \times \frac{a^{2} - 25}{a^{2} - a - 20} \div \frac{a^{2} - a - 2}{a^{2} + 2 a - 8}$ when simplified is equal to

A

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

\frac{1}{a}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

a^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{1}{a}$
$\frac{a + 1}{a^{2} + 5 a} \times \frac{a^{2} - 25}{a^{2} - a - 20} \div \frac{a^{2} - a - 2}{a^{2} + 2 a - 8}$
$\frac{a + 1}{a^{2} + 5 a} \times \frac{(a - 5) (a + 5)}{a^{2} - 5 a + 4 a - 20} \div \frac{a^{2} - 2 a + a - 2}{a^{2} + 4 a - 2 a - 8}$
$\frac{a + 1}{a^{2} + 5 a} \times \frac{(a - 5) (a + 5)}{(a - 5) (a + 4)} \div \frac{(a - 2) (a + 1)}{(a + 4) (a - 2)}$
$\frac{a + 1}{a^{2} + 5 a} \times \frac{a + 5}{a + 4} \times \frac{a + 4}{a + 1}$
$\frac{a + 5}{a^{2} + 5 a} = \frac{a + 5}{a (a + 5)} = \frac{1}{a}$

Suggest Corrections

thumbs-up

1

Similar questions

Q. Simplify the following expression:

(\frac{a}{a^{2} - 4} - \frac{8}{a^{2} + 2 a}) \times \frac{a^{2} - 2 a}{4 - a} + \frac{a + 8}{a + 2}

[\frac{1}{1 + a} + \frac{2 a}{1 - a^{2}}] \times \frac{(a^{2} + 4 a - 5)}{a^{2} + 10 a + 25}

\frac{a^{2} + 10 a + 21}{a^{2} + 6 a - 7} \times \frac{a^{2} - 1}{a + 3}

a^{2} + \frac{1}{a^{2}} - 2 - 3 a + \frac{3}{a}

a^{2} + \frac{1}{a^{2}} + 3 - 2 a - \frac{2}{a}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Extrema

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon