cos 67^∘/sin 23^∘ = nbsp; cos (90^∘ 23^∘)/sin 23^∘ = nbsp; sin 23^∘/sin 23^∘ = 1 ...

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Standard Formulae - 1

cos 67∘/sin 2...

Question

$\frac{cos 67^{\circ}}{sin 23^{\circ}}$

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Solution

$\frac{cos 67^{\circ}}{sin 23^{\circ}}$
= $\frac{cos (90^{\circ} - 23^{\circ})}{sin 23^{\circ}}$
= $\frac{sin 23^{\circ}}{sin 23^{\circ}}$ (Since Cos x and sin x are Complementary pair of angles, Cos(90-x) = Sin x)
= $1$

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