The correct option is B cosθ Write denominator as sec #160; θ cosec θ using the previous result ...

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Trigonometric Equations

cosecθ/θ +tan...

Question

$\frac{c o s e c θ}{cot θ + tan θ}$

sin θ

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cos θ

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tan θ

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cot θ

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Solution

The correct option is B $cos θ$
Write denominator as sec $sec θ c o s e c θ$ using the previous result

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Similar questions

\frac{sin θ}{(sec θ + tan θ - 1)} + \frac{cos θ}{c o s e c θ + cot θ - 1}

\frac{tan θ}{1 - tan θ} - \frac{cot θ}{1 - cot θ} = \frac{cos θ + sin θ}{cos θ - sin θ}

$\frac{t a n θ}{s e c θ}$ + $\frac{c o t θ}{c o s e c θ}$ in terms of $s i n θ$ and $c o s θ$ (if $s i n θ$ = x and $c o s θ$ = y) can be written as:

tan θ = - 1

\frac{sec θ - cos e c θ}{cos θ - sin θ},

\frac{3 π}{2} < θ < 2 π

\frac{cos θ}{sin θ} \times \frac{tan θ}{csc θ}

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