D-dxtan-1-x-x-1-x3-2-

The correct option is A 1/1+x.1/2√( ( x )) 1/1+x^2. Let #160; y=tan^ 1√(x) x/1+√( ( x )).x =tan^ 1√(x) tan^ 1x ∴dy/dx=1/1+x.1/2√( ( x ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Properties Derived from Trigonometric Identities

d/dxtan-1√x-x...

Question

$\frac{d}{d x} ({tan}^{- 1} \frac{\sqrt{x} - x}{1 + x^{3 / 2}} .)$

\frac{1}{1 + x} . \frac{1}{2 \sqrt{(x)}} - \frac{1}{1 + x^{2}} .

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{1 - x} . \frac{1}{2 \sqrt{(x)}} - \frac{1}{1 + x^{2}} .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{1 + x} . \frac{1}{2 \sqrt{(x)}} - \frac{1}{1 + x^{3}} .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- \frac{1}{1 + x} . \frac{1}{2 \sqrt{(x)}} - \frac{1}{1 + x^{2}} .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

lim x \to 1 (\frac{1}{x^{2} + x - 2} - \frac{x}{x^{3} - 1})

\int \frac{(x + a)^{3}}{x^{3}} + \frac{1 - x^{4}}{1 - x} - \frac{7}{x \sqrt{(x^{2} - 1)}} + \frac{x + 2}{(x^{2} + 1)^{2}} + \frac{(1 + x)^{3}}{\sqrt{(x)}} d x

x + k a l o g x - k \frac{a^{2}}{x} - \frac{a^{m}}{n x^{2}} + x + \frac{x^{2}}{2} + \frac{x^{3}}{3} + \frac{x^{4}}{4}

- 7 {sec}^{- 1} x + l o g (x + 1) - \frac{1}{x + 1} + 2 \sqrt{x} + 2 x^{3 / 2} + \frac{p}{5} x^{5 / 2} + \frac{2}{r} x^{7 / 2}

k + m + n + p - r

\frac{d}{d x} {tan}^{- 1} (\frac{1 - x}{1 + x}) =

x \neq 0

x + \frac{1}{x} = 2

x^{2} + \frac{1}{x^{2}} = x^{3} + \frac{1}{x^{3}} = x^{4} + \frac{1}{x^{4}}

x = \frac{5 - \sqrt{21}}{2}

(x^{3} + \frac{1}{x^{3}}) - 5 (x^{2} + \frac{1}{x^{2}}) + (x + \frac{1}{x}) =

Join BYJU'S Learning Program