CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Δ2a2+b2+c2{1r21+1r22+1r23+1r2}=

A
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4Rr2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1r
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1
FORMULA USED IN SOLVING PROBLEM

  1. s=a+b+c2
  2. r=Δs (∆ = area of triangle)
  3. r1=Δsa,r2=Δsb,r3=Δsc

Putting equation 2 and 3 in given expression , we get
=(sa)2+(sb)2+(sc)2+(s)2a2+b2+c2

Putting equation 1 in the expression , we get
=14×((a+b+c)2+(ab+c)2+(a+bc)2a2+b2+c2)

On expansion equation get simplified to
=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hooke's Law
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon