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Byju's Answer
Standard XII
Physics
Young's Modulus of Elasticity
Δ2/a2+b2+c21/...
Question
Δ
2
a
2
+
b
2
+
c
2
{
1
r
2
1
+
1
r
2
2
+
1
r
2
3
+
1
r
2
}
=
A
1
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B
0
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C
4
R
r
2
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D
1
r
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Solution
The correct option is
B
1
FORMULA USED IN SOLVING PROBLEM
s
=
a
+
b
+
c
2
r
=
Δ
s
(∆ = area of triangle)
r
1
=
Δ
s
−
a
,
r
2
=
Δ
s
−
b
,
r
3
=
Δ
s
−
c
Putting equation 2 and 3 in given expression , we get
=
(
s
−
a
)
2
+
(
s
−
b
)
2
+
(
s
−
c
)
2
+
(
s
)
2
a
2
+
b
2
+
c
2
Putting equation 1 in the expression , we get
=
1
4
×
(
(
−
a
+
b
+
c
)
2
+
(
a
−
b
+
c
)
2
+
(
a
+
b
−
c
)
2
a
2
+
b
2
+
c
2
)
On expansion equation get simplified to
=
1
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0
Similar questions
Q.
The value of
1
r
2
1
+
1
r
2
2
+
1
r
2
3
+
1
r
2
is