I4n - 3 - -i8n - 3-i12 n- 1 - i2 - 16 n- n - N is equal to

The correct option is B 1 iGiven expression nbsp; = i^3 + ( 1) (i)^ 3/( i)^ 1 (i)^2 = i i/ i + 1 = 2i/1 + i×1 i/1 i = nbsp; 2i 2 ...

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General Term of Binomial Expansion

i4n + 3 + -i8...

Question

$\frac{i^{4 n + 3} + (- i)^{8 n - 3}}{(i)^{12 n - 1} - i^{2 - 16 n}}, n ε N$ is equal to

1 + i

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-2i

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-1 - i

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Solution

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