The correct option is D 0.64 (0.35)^2 (0.03)^20.19 = (0.35+0.03)(0.35 0.03)0.19 #160; #160; [a^2 b^2=(a+b)(a b)] =(0.38)(0.32)0.19 ...

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Cube of a Number

0.35 2- 0.03 ...

Question

$\frac{{(0.35)}^{2} - {(0.03)}^{2}}{0.19} = ?$

0.32

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0.48

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0.76

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0.64

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Solution

The correct option is D 0.64
$\frac{(0.35)^{2} - (0.03)^{2}}{0.19}$ = $\frac{(0.35 + 0.03) (0.35 - 0.03)}{0.19}$ $[a^{2} - b^{2} = (a + b) (a - b)]$

$= \frac{(0.38) (0.32)}{0.19}$

$= 2 \times 0.32$

$= 0.64$

So the correct answer will option D

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