$\frac{{(2.3)}^{3} - 0.027}{{(2.3)}^{2} + 0.69 + 0.09} = ?$

2.6

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2

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2.33

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2.8

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Solution

The correct option is B $2$
$\frac{{(2.3)}^{3} - 0.027}{{(2.3)}^{2} + 0.69 + 0.09} = \frac{12.167 - 0.027}{5.29 + 0.69 + 0.09} = \frac{12.14}{6.07} = 2$
So, correct answer is option B.

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Similar questions

\frac{(2.3)^{3} - 0.027}{(2.3)^{2} + 0.69 + 0.09}

The value of $\frac{(2.3)^{3} - 0.027}{(2.3)^{2} + 0.69 + 0.09}$ is

[\frac{{(2.3)}^{3} - 0.027}{{(2.3)}^{2} + 0.69 + 0.09}]

The value of (2.3)³ -0.027/(2.3)²

+0.69 + (0.3)²

$T h e v a l u e o f \frac{(2.3)^{3} - .027}{({2.3}^{2} + 0.69 + 0.09)} i s$

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