X3-x2-x-2-x-k-x-2-x2-x-2-k-

The correct option is C 1 x^2 x+2)x^3 #160; #160; (x+1 x^3 x^2+2x x^2 2x x^2 x+2 x 2 LHS⇒ (x+1) [x+2](x^2 x+2) RH ...

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Byju's Answer

Standard XII

Mathematics

Integration by Partial Fractions

x3/x2-x+2=x+k...

Question

$\frac{x^{3}}{x^{2} - x + 2} = x + k - [\frac{x + 2}{x^{2} - x + 2}] \Rightarrow k =$

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Solution

The correct option is C $1$
$x^{2} - x + 2) x^{3} (x + 1$
$- x^{3} - x^{2} + 2 x$
$x^{2} - 2 x$
$x^{2} - x + 2$
$- x - 2$
$L H S \Rightarrow (x + 1) - \frac{[x + 2]}{(x^{2} - x + 2)}$
$R H S = (x + k) - [\frac{x + 2}{x^{2} - x + 2}]$
$k = 1$
the value of $k = 1$

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Similar questions

\int \frac{(x + a)^{3}}{x^{3}} + \frac{1 - x^{4}}{1 - x} - \frac{7}{x \sqrt{(x^{2} - 1)}} + \frac{x + 2}{(x^{2} + 1)^{2}} + \frac{(1 + x)^{3}}{\sqrt{(x)}} d x

x + k a l o g x - k \frac{a^{2}}{x} - \frac{a^{m}}{n x^{2}} + x + \frac{x^{2}}{2} + \frac{x^{3}}{3} + \frac{x^{4}}{4}

- 7 {sec}^{- 1} x + l o g (x + 1) - \frac{1}{x + 1} + 2 \sqrt{x} + 2 x^{3 / 2} + \frac{p}{5} x^{5 / 2} + \frac{2}{r} x^{7 / 2}

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Question 1
Which of the following is a quadratic equation?
(a) $x^{2} + 2 x + 1 = (4 - x)^{2} + 3$
(b) $- 2 x^{2} = (5 - x) (2 x - \frac{2}{5})$
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Q. If

\frac{x - 4}{x^{2} - 5 x - 2 k} = \frac{2}{x - 2} - \frac{1}{x + k}

, then

k =

Q. If

f (x) = \frac{x^{3} + x^{2} - 16 x + 20}{(x - 2)^{2}}, x \neq 2

= k, x = 2

is continuous at x=2, find the value of k.

Q. Find the limits :

i .

lim x \to 1 [\frac{x^{2} + 1}{x + 100}]

i i .

lim x \to 2 [\frac{x^{3} - 4 x^{2} + 4 x}{x^{2} - 4}]

i i i .

lim x \to 2 [\frac{x^{2} - 4}{x^{3} - 4 x^{2} + 4 x}]

i v .

lim x \to 2 [\frac{x^{3} - 2 x^{2}}{x^{2} - 5 x + 6}]

v .

lim x \to 1 [\frac{x - 2}{x^{2} - x} - \frac{1}{x^{3} - 3 x^{2} + 2 x}]

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x3x2−x+2=x+k−[x+2x2−x+2]⇒k=

The correct option is C 1x2−x+2)x3(x+1−x3−x2+2xx2−2xx2−x+2−x−2LHS⇒(x+1)−[x+2](x2−x+2)RHS=(x+k)−[x+2x2−x+2]k=1the value of k=1

$\frac{x^{3}}{x^{2} - x + 2} = x + k - [\frac{x + 2}{x^{2} - x + 2}] \Rightarrow k =$

The correct option is C $1$
$x^{2} - x + 2) x^{3} (x + 1$
$- x^{3} - x^{2} + 2 x$
$x^{2} - 2 x$
$x^{2} - x + 2$
$- x - 2$
$L H S \Rightarrow (x + 1) - \frac{[x + 2]}{(x^{2} - x + 2)}$
$R H S = (x + k) - [\frac{x + 2}{x^{2} - x + 2}]$
$k = 1$
the value of $k = 1$