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Question

sinA1+cosA+sinA1−cosA is equal to :

A
sinA
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B
2cosecA
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C
cosA
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D
None of these
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Solution

The correct option is B 2cosecA
sinA1+cosA+sinA1cosA
=sinA[1cosA+1+cosA(1+cosA)(1cosA)]
=sinA(2sin2A)=2sinA=2cosecA

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