Sin A - 1-cos A -sin A - 1-cos A is equal to -

The correct option is B 2cosecA sin A #160;/ 1+cos A #160; +sin A #160;/ 1 cos A #160; #160; =sin A[ 1 cos A +1+cos A #160;/( ...

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Relation between Inverses of Trigonometric Functions and Their Reciprocal Functions

sin A / 1+cos...

Question

$\frac{sin A}{1 + cos A} + \frac{sin A}{1 - cos A}$ is equal to :

sin A

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2 c o s e c A

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cos A

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None of these

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\frac{sin A}{1 + cos A} + \frac{1 + cos A}{sin A} = 2 c o s e c A .

\frac{1 + cos A}{sin A} + \frac{sin A}{1 + cos A} = 2 cosec A

\frac{sin A}{1 + cos A} + \frac{1 + cos A}{sin A} = 2 cosec A

Prove the following trigonometric identities:

(i) $\sqrt{\frac{1 + s i n A}{1 - s i n A}} = s e c A + t a n A$

(ii) $\sqrt{\frac{1 - c o s A}{1 + c o s A}} + \sqrt{\frac{1 + c o s A}{1 - c o s A}} = 2 c o s e c A$

\frac{1 + cos A - sin A}{1 + cos A + sin A} = sec A - tan A = \frac{1 - sin A}{cos A} = \sqrt{\frac{1 - sin A}{1 + sin A}}

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