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Question

sin(A+B)cosAcosB=tanA+tanB

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Solution

Given: A=60,B=30
Now, sin(A+B)cosAcosB=tanA+tanB
L.H.S.=sin(A+B)cosAcosB
= sin(600+300)cos600cos300
= sin900cos600cos300
= 1cos600cos300
= sec600sec300
= 23.2
= 43
R.H.S=tanA+tanB
= tan600+tan300
= 3+13
= 3+13
= 43
L.H.S=R.H.S
sin(A+B)cosAcosB=tanA+tanB


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