The correct option is A [0,3] ∪ [3,∞] R.E.F image #160; x^2 3xx 3≥ 0 x(x 3)x 3≥ 0 x≠ 3 xϵ [0,3) ∪ (3,∞ ) #160; #160; #160; ...

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Condition for Two Lines to Be Parallel

x 2 -3x / x-3...

Question

$\frac{x^{2} - 3 x}{x - 3} \geq 0$

[0, 3] \cup [3, \infty]

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[0, - \infty]

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[3, \infty]

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None of these

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Solution

The correct option is A $[0, 3] \cup [3, \infty]$
R.E.F image
$\frac{x^{2} - 3 x}{x - 3} \geq 0$
$\frac{x (x - 3)}{x - 3} \geq 0$
$x \neq 3$
$x ϵ [0, 3) \cup (3, \infty)$

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