X3-x-ax-bx-c-k-A-x-a-B-x-b-C-x-c- k-

The correct option is B 1 x^3/(x a)(x b)(x c)=k+A/(x a)+B/(x b)+C/(x c) the value of k is theIn order of N(x)=D(x) then value of k is the leading co e ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Solving Linear Differential Equations of First Order

x3/x-ax-bx-c=...

Question

$\frac{x^{3}}{(x - a) (x - b) (x - c)} = k + \frac{A}{x - a} + \frac{B}{x - b} + \frac{C}{x - c} \Rightarrow k =$

abc

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a+b+c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ab+bc+ca

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B 1
$\frac{x^{3}}{(x - a) (x - b) (x - c)} = k + \frac{A}{(x - a)} + \frac{B}{(x - b)} + \frac{C}{(x - c)}$
the value of k is the
In order of $N (x) = D (x)$
then value of k is the leading co-efficient
$= \frac{o + N (x)}{t h e l e a d i n g c o - e f f i c i e n t o f D (x)}$
$= \frac{1}{1}$
$k = 1$

Suggest Corrections

Similar questions

Q. If

\frac{x^{3}}{(x - a) (x - b) (x - c)} = 1 + \frac{A}{x - a} + \frac{B}{x - b} + \frac{C}{x - c}

then

A =

Q. If

x^{3} - 2 x^{2} - x + 2 = (x - a) (x + b) (x - c)

.Find

a + b + c

Q. Solve the following equations :
(a)

\frac{x - a}{b c} + \frac{x - b}{c a} + \frac{x - c}{a b}

= 2

(\frac{1}{a} + \frac{1}{b} + \frac{1}{c})

(b)

\frac{(x - a) (x - b)}{x - a - b} = \frac{(x - c) (x - d)}{x - c - d}

Q. If

x^{3} + 13 x^{2} + 32 x + 20 = (x + a) (x + b) (x + c)

.Find

a + b + c

Q. If

(x + a) (x + b) (x + c) = x^{3} - 10 x^{2} + 45 x - 15

find

- (a + b + c)

Join BYJU'S Learning Program

x3(x−a)(x−b)(x−c)=k+Ax−a+Bx−b+Cx−c⇒k=

The correct option is B 1x3(x−a)(x−b)(x−c)=k+A(x−a)+B(x−b)+C(x−c)the value of k is theIn order of N(x)=D(x)then value of k is the leading co-efficient=o+N(x)theleadingco−efficientofD(x)=11k=1

$\frac{x^{3}}{(x - a) (x - b) (x - c)} = k + \frac{A}{x - a} + \frac{B}{x - b} + \frac{C}{x - c} \Rightarrow k =$