$H C l (g)$ and $H C l (a q)$ have different behaviour towards litmus.

True

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False

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Solution

The correct option is A True
$H C l$ can produce ions only in aqueous solution making aqueous $H C l$ acidic. So, aqueous $H C l$ turns blue litmus red whereas dry $H C l$ does not dissociate and acts inert to litmus.

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Similar questions

N H_{3} (g) + H C l (g) \to N H_{4} C l (s)

N H_{3} (g) + a q \to N H_{3} (a q),

Δ H = - 8.4 K . C a l .

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Δ H = - 17.3 K . C a l .

N H_{3} (a q) + H C l (a q) \to N H_{4} C l (a q), Δ H = - 12.5 K . C a l s .

N H_{4} C l (s) + a q \to N H_{4} C l (a q), Δ H = + 3.9 K . C a l .

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2 A l (s) + 6 H C l (a q) \to A l_{2} C l_{6} (a q) + 3 H_{2} (g), △ H = - 239.76 k c a l

H_{2} (g) + C l_{2} (g) \to 2 H C l (g), △ H = - 44.0 k c a l

H C l (g) + A q \to H C l (a q), △ H = - 17.32 k c a l

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(b) $N a_{2} C O_{3} (s) + H C l (a q) \to$

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(e) $C u O (s) + H C l (a q) \to$

A l_{2} C l_{6}

2 A l (s) + 6 H C l (a q) ⟶ A l_{2} C l_{6} (a q) + 3 H_{2} + 1004.2 k J

H_{2} (g) + C l_{2} (g) ⟶ 2 H C l (g) + 184.1 k J

H C l (g) + a q ⟶ H C l (a q) + 73.2 k J

A l_{2} C l_{6} (s) + a q ⟶ A l_{2} C l_{6} (a q) + 643.1 k J

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