HCl aq -Zn s - Zn l 2 aq - H 2 g In the above reaction HCl aq play a role as -

The correct option is A oxidizing agent HCl + Zn → ZnI_2 + H_2 Here, as the Zn is oxidized to Zn^2+ , so here, HCl play a role as oxidizing agen ...

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Oxidising Reagent and Reducing Reagent

HCl aq +Zn s ...

Question

$H C l (a q) + Z n (s) \to Z n l_{2} (a q) + H_{2} (g)$
In the above reaction $H C l (a q)$ play a role as :

bronsted acid

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oxidizing agent

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reducing agemt

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precipitate

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cathode

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Solution

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Similar questions

H C l (a q) + Z n (s) \to Z n {C l}_{2} (a q) + H_{2} (g)

H C l (a q)

Complete and balance the following chemical equations :

(a) $Z n (s) + H C l (a q) \to$

(b) $N a_{2} C O_{3} (s) + H C l (a q) \to$

(d) $N a O H (a q) + H C l (a q) \to$

(e) $C u O (s) + H C l (a q) \to$

$A g N O_{3} (a q) + H C l (a q) \to P r o d u c t$

In the above reaction, the product formed as a precipitate is :

H C l_{(a q)} + N H_{3 (a q)} ⇌ {C l}_{(a q)}^{-} + N H_{4 (a q)}^{+}

H C l (a q)

Z n (s)

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