$H F$ attacks glass $({N a}_{2} {S i O}_{3})$ forming :

({N a}_{2} {S i F}_{4})

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({N a}_{2} {S i F}_{3})

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({N a}_{2} {S i F}_{6})

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(H_{4} {S i O}_{4})

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Solution

The correct option is C $({N a}_{2} {S i F}_{6})$
$H F$ attacks glass $({N a}_{2} {S i O}_{3})$ forming ${N a}_{2} {S i F}_{6}$ .
$({N a}_{2} {S i O}_{3}) + 6 H F \to ({N a}_{2} {S i F}_{6}) + 3 H_{2} O$

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