${H g}_{2} {C l}_{2}$ is blackened by ${N H}_{3}$ due to formation of iodide of Millon's base.

If the given statement is true enter 1 else enter 0.

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Solution

The given statement, " ${H g}_{2} {C l}_{2}$ is blackened by ${N H}_{3}$ due to formation of iodide of Millon's base." is not true
${H g}_{2} {C l}_{2}$ reacts with ammonia to form $({H g N H}_{2} C l + H g)$ . It is black in colour.
$H g_{2} C l_{2} + 2 N H_{4} O H \to H_{2} N - H g - C l + H g ↓ b l a c k + N H_{4} C l + 2 H_{2} O$
$H g_{2} C l_{2}$ is not blackened due to formation of Million's base.

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