$\int_{0}^{1} \sqrt{\frac{1 + x}{1 - x}} d x$

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Solution

$\int_{0}^{1} \sqrt{\frac{1 - x}{1 - x}} d x = \int_{0}^{1} \sqrt{1} d x = 1 - 0 = 1$

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Similar questions

L e t I = 1 \int 0 \sqrt{\frac{1 + \sqrt{x}}{1 - \sqrt{x}}} d x

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