$\int_{0}^{1} x^{2} + 2 x d x$

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Solution

$\int_{0}^{1} x^{2} + 2 x d x \int_{0}^{1} x^{2} d x + \int_{0}^{1} 2 x d x {\frac{x^{3}}{3} + x^{2} ∣ ∣ ∣}_{0}^{2} \frac{1}{3} + 1 = \frac{4}{3}$

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