$\int_{0}^{3} [x] d x$ is equal to

2

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3

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1

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Solution

The correct option is B $3$
$\int_{0}^{3} [x] d x = \int_{0}^{1} [x] d x + \int_{1}^{2} [x] d x + \int_{2}^{3} [x] d x$
$\Rightarrow \int_{0}^{3} [x] d x = \int_{0}^{1} 0 d x + \int_{1}^{2} 1 d x + \int_{2}^{3} 2 d x = (2 - 1) + 2 (3 - 2) = 3$

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The correct option is B 3∫30[x]dx=∫10[x]dx+∫21[x]dx+∫32[x]dx⇒∫30[x]dx=∫100dx+∫211dx+∫322dx=(2−1)+2(3−2)=3

$\int_{0}^{3} [x] d x$ is equal to

The correct option is B $3$
$\int_{0}^{3} [x] d x = \int_{0}^{1} [x] d x + \int_{1}^{2} [x] d x + \int_{2}^{3} [x] d x$
$\Rightarrow \int_{0}^{3} [x] d x = \int_{0}^{1} 0 d x + \int_{1}^{2} 1 d x + \int_{2}^{3} 2 d x = (2 - 1) + 2 (3 - 2) = 3$