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Question

0x2dx(1+x2)7/2=

A
1/15
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B
2/15
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C
-1/15
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D
415
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Solution

The correct option is C 2/15

x=tanθ
π20tan2θsec7θsec2θdθ
=π20sin2θcos3θdθ
=π20(1cos2θ)cos3θdθ
π20cos3θdθπ20cos5θdθ
=[23][45×23]
=23(15)=215


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