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Question

π/20sinx1+cosxdx=

A
21
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B
22
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C
2(21)
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D
2+12
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Solution

The correct option is D 2(21)
I=π/20sinx1+cosxdx

Let t=1+cosxdt=sinxdx

limit of t : when x=0,t=2

when x=π2,t=1

I=12dtt=21dtt

=2[t]21

=2[21]

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