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Question

22xdx(1+x4)(1+x2)=

A
π4
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B
0
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C
π12
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D
π24
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Solution

The correct option is A 0
Let, I=22xdx(1+x4)(1+x2)
Now using baf(x)dx=baf(a+bx)dx
I=22(x)dx(1+(x)4)(1+(x)2)=22xdx(1+x4)(1+x2)=I
I+I=0I=0

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