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Question

32|x25x+6|dx=

A
1/6
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B
2/3
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C
4/7
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D
3/7
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Solution

The correct option is B 1/6

32|x25x+6|dx
32(+x25x+6)dx
[x33325(x22)32+6(x)32]
[9835(922)+6]
[983452+10+6]
=[16]=16


64943_30948_ans_54f985b9cffa4e49a1d97eb8c34f532b.png

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